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|A
|
|
| 60
|__________|___________45_
B. C. D

Join A to C and D

Let

Height of the aeroplane from the

ground = AB = 200m



Width of the river = CD

i) In right TRIANGLE ABD,

tan 45° = AB / BD

1 = 200 / BD

BD = 200m ---( 1 )

ii ) In triangle ABC ,

Tan 60° = AB / BC

√3 = 200 / BC

BC = 200 /√3

BC =( 200 √3)/( √3 × √3 )

BC = 200√3 / 3----( 2 )

iii ) width of the river =

CD = BD - BC

= 200 - 200√3/3

= 200( 1 - √3 /3)

= 200( 3 - √3 )/3

=( 200/3) ( 3 - √3 ) m

I hope this helps you.

:)


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