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| 1. |
Sn | Sn C12 (1M) ; Egn2t/sn = -0.14VFel Fes04 (1M) ; EºFe2+/Fe =-0.44 |
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Answer» E°cell= E°cathode - E°anode = -0.14 + 0.44 = 0.30 V |
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