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∞Σn₋₁ 4(1/3)ⁿ⁻₁need help finding the sum of the geometric series |
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Answer» Answer: CORRECT Answer is 6 4+4[(1/3)]+4[(1/3)^2+..... .............+INFINITE] 4[1/(1-1/3)] 4*3/2=6 Step-by-step explanation: |
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