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Sketch the graph of `y=|x+3|`and evaluate thearea under the curve `y=|x+3|`above x-axisand between `x=6` to `x=0.` |
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Answer» `y = x+3`, when `x ge -3` `y = -x-3`, when `x lt -3` So, now we can draw the graph using these two equations. Please refer to video to see the graph. We have to find the area between `x = -6` to `x = 0`. From the graph, we can see that required area is area of two right angle triangles. `:.` Required Area `= 2(1/2*3*3) = 9` square units. |
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