1.

Sketch the graph of `y=|x+3|`and evaluate thearea under the curve `y=|x+3|`above x-axisand between `x=6` to `x=0.`

Answer» `y = x+3`, when `x ge -3`
`y = -x-3`, when `x lt -3`
So, now we can draw the graph using these two equations.
Please refer to video to see the graph.
We have to find the area between `x = -6` to `x = 0`.
From the graph, we can see that required area is area of two right angle triangles.
`:.` Required Area `= 2(1/2*3*3) = 9` square units.


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