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Six years ago a man was three times as old as his son. In 6 year’s time, he will be twice as old as his son. Then their present ages are A) 30, 15 B) 40, 20 C) 42, 18 D) 41, 19 |
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Answer» Correct option is (C) 42, 18 Let present age of son be x years and present age of father be y years. Then according to given conditions, we get y - 6 = 3 (x - 6) \(\Rightarrow\) y = 3x - 12 ____________(1) and y + 6 = 2 (x+6) \(\Rightarrow\) 2x+12 = y+6 \(\Rightarrow\) 2x - y + 6 = 0 ____________(2) From (1) & (2), we get 2x - (3x - 12) + 6 = 0 \(\Rightarrow\) 2x - 3x + 12 + 6 = 0 \(\Rightarrow\) x = 18 \(\therefore\) y = 3x - 12 = 54 - 12 = 45 (From (1)) Hence, their present ages are 18 & 42 years. Correct option is C) 42, 18 |
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