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Six dice are thrown simultaneously. The probability that all of them show the different faces, isA. `(1)/(6^(5))`B. `(6!)/(6^(6))`C. `(1)/(6!)`D. `(5!)/(6!)`

Answer» Correct Answer - B
The total number of ways in which all dice show different faces is same as the number of arrangements of 6 numbers 1,2,3,4,5,6 by taking all at a time.
So, favourable number of elementary events -6 !
Hence, required probaility `=(6!)/(6^(6))`


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