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Six dice are thrown simultaneously. The probability that all of them show the different faces, isA. `(1)/(6^(5))`B. `(6!)/(6^(6))`C. `(1)/(6!)`D. `(5!)/(6!)` |
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Answer» Correct Answer - B The total number of ways in which all dice show different faces is same as the number of arrangements of 6 numbers 1,2,3,4,5,6 by taking all at a time. So, favourable number of elementary events -6 ! Hence, required probaility `=(6!)/(6^(6))` |
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