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Sinusoidal waves `5.00 cm ` in amplitude are to be transmitted along a string having a linear mass density equal to `4.00xx10^-2kg//m`. If the source can deliver a maximum power of `90W` and the string is under a tension of `100N`, then the highest frequency at which the source can operate is (take `pi^2=10`)A. `45.3Hz`B. `50Hz`C. `30Hz`D. `62.3Hz` |
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Answer» Correct Answer - C Sinusodial waves ………….. `(C )P = (1)/(2) mu omega^(2) A^(2)V` using `V = sqrt((T)/(mu))` `P = (1)/(2)omega^(2)A^(2) sqrt(T mu)` `omega = sqrt((2P)/(A^(2)sqrt(T mu))) f = (omega)/(2pi) = (1)/(2pi) sqrt((2P)/(A^(2)sqrt(T mu)))` using data `f = 30 Hz`. |
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