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(sine a +sec a)2 +(cose a+cosec a)2=(1+sec a+cosec a)2 |
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Answer» Taking L.H.S consider (^) = power square (sinA + secA)^ + (cosA + cosecA)^ (1/cosecA + secA)^ + ( 1/ secA. + cosecA)^ [( 1 + secA× cosecA)/cosecA]^ + [ (1 +cosecA×secA)/secA]^ (1 + secA×cosecA)^/cosecA^ + ( 1 + cosecA×secA)^/ secA^ taking common , (1 + secA× cosecA)^ (1/cosec^A + 1/ sec^A) (1 + secA× cosecA)^ (sin^A +cos^A) (1 + secA×cosecA)^ (1) ( 1 + secAcosecA)^ it has proved, L.H.S = R.H.S thanks |
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