1.

SinA × tanA /1-cosA = 1+secA​

Answer»

ANSWER:

L.H.S- SINA×tanA/1-COSA

= sinA× sinA/cosA/1-cosA

=sinA ×sinA/cosA(1-cosA)

=sin2A/cosA(1-cosA)

=1-cos2A/cosA(1-cosA)

= (1-cosA)(1+cosA)/cosA(1-cosA)

= (1+cosA)/cosA

= 1/cosA + cosA/cosA

= secA+1

now, R.H.S= 1+secA

so, L.H.S= R.H.S



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