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| 1. |
SinA+sinB+sinC=S/R |
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Answer» We know a/sinA=b/sinB=c/sinC=2R So a/(2R)=sinA b/(2R)=sinB c/(2R)=sinC Now sinA+sinB+sinC =1/(2R)[a+b+c) =2s/(2R)=s/R Proved |
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