1.

SinA+sinB+sinC=S/R

Answer» We know

a/sinA=b/sinB=c/sinC=2R

So a/(2R)=sinA

b/(2R)=sinB

c/(2R)=sinC

Now

sinA+sinB+sinC

=1/(2R)[a+b+c)

=2s/(2R)=s/R

Proved


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