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SinA+sin3A+sin5A+sin7A= |
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Answer» Step-by-step EXPLANATION: SinA+sin3A+sin5A+sin7A/cosA+cos3A+cos5A+cos7A =(sinA+sin7A)+(sin3A+sin5A)/(cosA+cos7A)+(cos3A+cos5A) =(2sin4Acos3A+2sin4AcosA)/(2cos4Acos3A+2cos4AcosA) =2sin4A(cos3A+cosA)/2cos4A(cos3A+cosA) =sin4A/cos4A =tan4A (PROVED) *MARK AS BRAINLIEST* |
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