: +SiNA - gecA+tan A1-sinAsin 0 - 2 sin® 6कक —tan®

1.	: +SiNA - gecA+tan A1-sinAsin 0 - 2 sin® 6कक —tan®
Answer» vi) LHS = √(1 + sin∅)/√(1 - sin∅) = √(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅) = √(1 + sin∅)²/√(1 -sin²∅) = (1 + sin∅)/√cos²∅ = (1 + sin∅)/cos∅ = 1/cos∅ + sin∅/cos∅ = sec∅ + tan∅ = RHS vii) let theta =x =sinx(1 - 2sin2x)/ cosx(2cos2x - 1) =sinx[1 -2(1 -cos2x)]/cosx(2cos2x - 1) =sinx[1 - 2 + 2cos2x]/cosx(2cos2x - 1) =sinx[2cos2x - 1]/cosx(2cos2x - 1) =sinx/cosx = tanx = rhs Like my answer if you find it useful!

Answer»

vi) LHS = √(1 + sin∅)/√(1 - sin∅)

= √(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅)

= √(1 + sin∅)²/√(1 -sin²∅)

= (1 + sin∅)/√cos²∅

= (1 + sin∅)/cos∅

= 1/cos∅ + sin∅/cos∅

= sec∅ + tan∅ = RHS

vii) let theta =x

=sinx(1 - 2sin2x)/ cosx(2cos2x - 1)

=sinx[1 -2(1 -cos2x)]/cosx(2cos2x - 1)

=sinx[1 - 2 + 2cos2x]/cosx(2cos2x - 1)

=sinx[2cos2x - 1]/cosx(2cos2x - 1)

=sinx/cosx

= tanx = rhs

Like my answer if you find it useful!

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