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(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca) |
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Answer» Answer: [sina+cosa]^2-1-{1-sina+cosa+sina-sin^2a+sinacosa-cosa-sinacosa+cos^2a}=2[1+1/sina] sin^2a+cos^2a+2sinacosa-1-1-cos^2a+sin^2a-2cosasina sin^2a-cos^2a-1 sin^2a-cos^2a-sin^2a-cos^2a -2cos^2a is REQUIRED answer Step-by-step EXPLANATION: PLEASE GIVE BRAINLIEST MARK. I NEED IT URGENTLY FOR RANK UP. PLEASE |
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