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SinA/1+cosA + 1+cosA/sinA = 1cosecA |
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Answer» Answer: LHS= cosA+sinA−1 cosA−sinA+1
dividing Nr and DR by sinA we get, = sinA cosA
+ sinA sinA
− sinA 1
sinA cosA
− sinA sinA
+ sinA 1
= cotA+1−cosecA cotA−1+cosecA
= cotA+1−cosecA cotA+cosecA−(cosec 2 A−cot 2 A)
= cotA+1−cosecA (cotA+cosecA)(1−cosecA+cotA)
=cotA+cosecA=RHS Step-by-step EXPLANATION: hope it HELPS u |
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