1.

sinA/ 1+ cosA + 1+cosA/ Sin=2cosecA

Answer»

(sinA/1+cosA) + (1+cosA/sinA) = 2(cosec A)

LHS:(sinA/1+cosA)+(1+cosA/sinA)

=sinA.sinA+(1+cosA). (1+cosA)/sinA(1+cosA)

=sin^2A+1+cos^2A+2cosA/. sinA(1+cosA)

=(2+2cosA) /sinA(1+cosA)

=2(1+cosA)/sinA(1+cosA)

=2sinA

=2(cosec A)

= RHS

Hence proved



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