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sinA/ 1+ cosA + 1+cosA/ Sin=2cosecA |
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Answer» (sinA/1+cosA) + (1+cosA/sinA) = 2(cosec A) LHS:(sinA/1+cosA)+(1+cosA/sinA) =sinA.sinA+(1+cosA). (1+cosA)/sinA(1+cosA) =sin^2A+1+cos^2A+2cosA/. sinA(1+cosA) =(2+2cosA) /sinA(1+cosA) =2(1+cosA)/sinA(1+cosA) =2sinA =2(cosec A) = RHS Hence proved |
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