1.

Sin4Q+cos4Q/1-2sin2Q.cos2Q=1

Answer»

Answer:

EXPLANATION:-

LHS,

=>sin^4Q+cos^4Q/1-2sin^2Q*cos^2Q.

=>(sin^2Q)^2+(cos^2Q)^2/1-2sin^2Q*cos^2Q.

=>(sin^2Q+cos^2Q)^2-2cos^2Q*sin^2Q/1-2 cos^2Q*sin^2Q .

=>1-2cos^2Q*sin^2Q/1-2cos^2Q*sin^2Q.

Now , numerator and denominator will be cancelled out.

=>1, RHS.

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Formula USED.

  • (a^2+ b^2)=(a+b)^2-2ab.
  • Sin^2A+cos^2A=1.

Step-by-step explanation:

HOPE it will help you.


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