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sin3x =? |
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Answer» sin 3x = sin(x + 2x)sin(x + 2x) = sinxcos2x + cosxsin2x Subtituting the values of sin2x and cos2x we get sin 3x = (sinx)(1−2sin^2x) +(cosx)(2sinxcosx) sin 3x = 3sinx−4sin^2 3x sin3x = 3sinx-4sin^3x |
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