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sin20.sin40.sin60.sin80=? |
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Answer» => sin60[sin20.sin40.sin80] =>√3/2[sin20.sin(60-20).sin(60+20)] =>√3/2[sin 3(20)/4] =>√3/2[sin 60/4] =>√3/2[√3/2*4] =>√3/2*√3/8 =3/16 thanks |
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