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| 1. |
Sin20.Sin40.sin60.sin80=3/16 (prove that ) |
| Answer» sin20. sin 40. sin60. sin80\xa0=> sin60[sin20.sin40.sin80]\xa0=>√3/2[sin20.sin(60-20).sin(60+20)]\xa0=>√3/2[sin 3(20)/4]\xa0=>√3/2[sin 60/4]\xa0=>√3/2[√3/2*4]\xa0=>√3/2*√3/8\xa0=3/16\xa0 | |