1.

Sin'x + sin'1/x +cos'1/x + cos'1/x is equal to​

Answer»

Step-by-step explanation:

LET [MATH]\theta = \sin^{-1}(x) \IMPLIES x = \sin(\theta)[/math]

[math]\COS^{-1}(x) = \cos^{-1} (\sin \theta) = \cos^{-1} (\cos (\dfrac{\pi}{2} - \theta) ) = \dfrac{\pi}{2} - \theta[/math]

[math]\sin^{-1}(x) + \cos^{-1}(x) = \theta + \dfrac{\pi}{2} - \theta = \dfrac{\pi}{2}[/math]

ANS: [math]\dfrac{\pi}{2}[/math]


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