(Sin Theta + Cos Theta)^2 + (Sin-Cos Theta)^2^1/2

1.	(Sin Theta + Cos Theta)^2 + (Sin-Cos Theta)^2^1/2
Answer» [(sinA + cosA)2 + (sinA - cosA)2] 0.5 = [ 2 { (sinA)2 + (cosA)2 }] 0.5 = (21)0.5 = 2*0.5 Sorry I did a mistake 2 1 Root 2

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