sin θ1+cos θis equal to(a) 1+cos θsin θ(b) 1-cos θcos θ(c) 1-cos θsin θ(d) 1-sin θcos θ

sin θ1+cos θis equal to(a) 1+cos θsin θ(b) 1-cos θcos θ(c) 1-cos

1.	sin θ1+cos θis equal to(a) 1+cos θsin θ(b) 1-cos θcos θ(c) 1-cos θsin θ(d) 1-sin θcos θ
Answer» $\frac{\sin θ}{1 + \cos θ}$ is equal to (a) $\frac{1 + \cos θ}{\sin θ}$ (b) $\frac{1 - \cos θ}{\cos θ}$ (c) $\frac{1 - \cos θ}{\sin θ}$ (d) $\frac{1 - \sin θ}{\cos θ}$