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Sin + sin 2 / 1+cos + cos 2 |
Answer» Questionsinθ + sin²θ/1 + cosθ + cos2θ = tanθExplanation:SIN(2θ) = 2sinθcos θcos(2θ) = 2cos2θ − 1tanθ = sinθcosθTherefore,LHS = (sinθ+sin2θ/(1+cosθ+cos2θ)= (sinθ+2sinθcosθ)/(1+cosθ+2cos2θ−1)= sinθ(1+2cosθ) / cosθ(1+2cosθ)= tanθ= RHS |
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