`Sin[pi/3-sin^(-1)(-1/2)]`A. 1B. 0C. `-1/2`D. none of these

1.	`Sin[pi/3-sin^(-1)(-1/2)]`A. 1B. 0C. `-1/2`D. none of these
Answer» Correct Answer - A `sin{pi/3-sin^(-3)(-1/2)}=sin{pi/3+sin^(-1)1/2}=sin(pi/3+pi/6)=sinpi/2=1`.

Discussion

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