1.

- sin—cos B+ 1 ¥] करें कि - एप्पलकि. | सिद्ध झा 0+ 05 6-1. 8९८9- (खा.

Answer»

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved



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