1.

Sin (A-B) =SinA CosB -CosA SinB. find the value of sin15.​

Answer»

ANSWER:

SIN 15° =

\sqrt{3}  - 1 \div 2 \sqrt{2}

Step-by-step EXPLANATION:

SIN15 = sin(45° - 30°)

sin45cos30 - cos45sin30

1/√2 × √3/2 - 1/√2 × 1/2

√3/2√2 - 1/2√2

= √3 - 1/2√2



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