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sin A /1+cosA+1+cosA/sinA

Answer»

=sinA/1+cosA + 1+cosA/sinA = [sin^2A + (1 + cosA)^2]/sinA(1 + cosA)= (sin^2A + 1 + cos^2A + 2cosA)/sinA(1 + cosA) = (1 + 1 + 2cosA)/sinA(1 + cosA) [since,sin^2A + cos^2A = 1] = (2 + 2cosA)/sinA(1 + cosA) = 2(1 + cosA)/sinA(1 + cosA) = 2/sinA = 2 cosecA [since 1/sinA = cosecA] = R.H.S



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