1.

Sin (90 °+A)/cos(-A)-sin (180°-A)/sin(-A)+tan(270°+A)/cot(-A)=3

Answer» SIN(90 + A) = COS(A)
cos(-A) = cos(A)
sin(180-A) = sin(A)
sin(-A) = -sin(A)
TAN(270+A) = -COT(A)
cot(-A) = - cot (A)

So,
=cos(A)/cos(A) - sin(A)/-sin(A) + (-cot(A))/-cot(A)

=1+1+1
=3


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