\sin ^{8} \theta-\cos ^{8} \theta=\left(\sin ^{2} \theta-\cos ^{2} \th – InterviewSolution

1.	\sin ^{8} \theta-\cos ^{8} \theta=\left(\sin ^{2} \theta-\cos ^{2} \theta\right)\left(1-2 \sin ^{2} \theta \cos ^{2} \theta\right)
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