sin(50^circ)*cos(10^circ) %2B sin(10)*cos(50^circ) – InterviewSolution

1.

sin(50^circ)cos(10^circ) %2B sin(10)cos(50^circ)

Answer»

sin (a + b) = sin a cos b + cos a sin b

then: Sin 50 ° cos 10 ° + cos 50 ° sin 10 ° = Sin (50 + 10) = sin 60 = 1/2 √3

by using sin (A+B)=sinAcosB+cosAsinB sin(50+10)=sin50cos10+cos10sin50 .. .sin (50+10)=sin 60 =root3/2

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