Sin 45 sin 30+ cos 40 cos 30 find

1.	Sin 45 sin 30+ cos 40 cos 30 find
Answer» ONG>Step-by-step explanation: GIVEN that Sin 45°Sin30°+Cos45°COS 30° =>(1/√2)(1/2)+(1/√2)(√3/2) =>(1/2√2)+(√3/2√2) =>(1+√3)/2√2 Sin 45°Sin30°+Cos45°Cos 30° Cos45°Cos 30°+Sin 45°Sin30° Here, A=45° ,B=30° This is in the FORM of Cos A Cos B+Sin A Sin B We know that Cos A Cos B+Sin A Sin B=Cos(A-B) Cos45°Cos 30°+Sin 45°Sin30°=Cos(45°-30°)=Cos15° Cos 15°=(1+√3)/2√2

Answer» ONG>Step-by-step explanation:

GIVEN that

Sin 45°Sin30°+Cos45°COS 30°

=>(1/√2)(1/2)+(1/√2)(√3/2)

=>(1/2√2)+(√3/2√2)

=>(1+√3)/2√2

Sin 45°Sin30°+Cos45°Cos 30°

Cos45°Cos 30°+Sin 45°Sin30°

Here, A=45° ,B=30°

This is in the FORM of

Cos A Cos B+Sin A Sin B

We know that

Cos A Cos B+Sin A Sin B=Cos(A-B)

Cos45°Cos 30°+Sin 45°Sin30°=Cos(45°-30°)=Cos15°

Cos 15°=(1+√3)/2√2

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Sin 45 sin 30+ cos 40 cos 30 find

GIVEN that

Sin 45°Sin30°+Cos45°COS 30°

=>(1/√2)(1/2)+(1/√2)(√3/2)

=>(1/2√2)+(√3/2√2)

=>(1+√3)/2√2

Sin 45°Sin30°+Cos45°Cos 30°

Cos45°Cos 30°+Sin 45°Sin30°

Here, A=45° ,B=30°

This is in the FORM of

Cos A Cos B+Sin A Sin B

We know that

Cos A Cos B+Sin A Sin B=Cos(A-B)

Cos45°Cos 30°+Sin 45°Sin30°=Cos(45°-30°)=Cos15°

Cos 15°=(1+√3)/2√2

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