sin(-45^circ %2B theta) %2B cos(45^circ %2B theta)=1

1.	sin(-45^circ %2B theta) %2B cos(45^circ %2B theta)=1
Answer» plz...tell us what we want to do in this... the answer of this question is 1 the answer of this question is 0 (zero) The answer of the question is zero.in place of cos(a+45) we should take cos(90+a-45)Then it will come as -sin(a-45)= sin( a-45)- sin( a-45)=0 cos(180+45)+ sin(180-45)÷ cos(45)-sin45=2/V2-2/V2=0

Answer»

plz...tell us what we want to do in this...

the answer of this question is 1

the answer of this question is 0 (zero)

The answer of the question is zero.in place of cos(a+45) we should take cos(90+a-45)Then it will come as -sin(a-45)= sin( a-45)- sin( a-45)=0

cos(180+45)+ sin(180-45)÷ cos(45)-sin45=2/V2-2/V2=0

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