\sin 120 ^ \circ %2B \tan 150 ^ \circ \cdot \cos 135 ^ \c – InterviewSolution

1.

\sin 120 ^ \circ %2B \tan 150 ^ \circ \cdot \cos 135 ^ \circ = \frac 3 %2B \sqrt 2 2 \sqrt 3

Answer»

sin(90+30) = cos 30tan (90+60)= -cot 60cos(135)= cos(90+45)= -sin45=

3+√2/2√3

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