1.

Simplify the following : ​

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\huge \fbox \orange{Solutions:}

1. \:  \sqrt{45}  - 3 \sqrt{20}  + 4√5

\sf \colorbox{pink} {<klux>ANSWER</klux>. 1}

\sqrt{45}  - 3 \sqrt{20}  + 4√5

=  \sqrt{3 \times 3 \times 5}  - 3 \sqrt{2 \times 2 \times 5}  + 4 \sqrt{5}

= 3 \sqrt{5}  - 3 \times 2 \sqrt{5} + 4 \sqrt{5}

= 3 \sqrt{5}  - 6 \sqrt{5}  + 4 \sqrt{5}

= 7 \sqrt{5}  - 6 \sqrt{5}

=  \sqrt{5}

2. \:  \frac{ \sqrt{24} }{8}  +   \frac{ \sqrt{54} }{9}

\sf \colorbox{pink} {Answer. 2}

\textbf{Given:}  \frac{ \sqrt{24} }{8}  +   \frac{ \sqrt{54} }{9}

SOLUTION:

= \frac{ \sqrt{24} }{8}  +   \frac{ \sqrt{54} }{9}

=  \frac{ \sqrt{2 \times 2 \times 2 \times 3} }{8}  +  \frac{ \sqrt{2 \times 3 \times 3} }{9}

⇒ \frac{2 \sqrt{2 \times 3} }{8}  +  \frac{3 \sqrt{2 \times 3} }{9}  =  \frac{ \sqrt{6} }{4}  +   \frac{ \sqrt{6} }{3}

⇒  \sqrt{6}  \left(  \frac{1}{4}  +  \frac{1}{3} \right) \] =  \sqrt{6}  \times  \frac{7}{12}

=  \frac{7}{12}  \sqrt{6}

3. \:  \:  \sqrt{3}  - 2 \sqrt{27}  +  \frac{7}{ \sqrt{3} }

\sf \colorbox{pink} {Answer. 3}

\textbf{Given:} \sqrt{3}  - 2 \sqrt{27}  +  \frac{7}{ \sqrt{3} }

Solution:

⇒3 \sqrt{3}   -  2 \sqrt{27}  +  \frac{7}{ \sqrt{3} }

⇒3 \sqrt{3 }   -  6 \sqrt{3}  +  \frac{7}{ \sqrt{3} }

⇒9 \sqrt{3}  -  \frac{7}{ \sqrt{3} } =   \left( \frac{9 \sqrt{3} }{ \sqrt{3} }   \times  \sqrt{3} \right) \] +  \frac{7}{3}

⇒ \frac{27}{ \sqrt{3} }  +  \frac{7}{ \sqrt{3} }  =  \frac{34}{ \sqrt{3} }

4. \:  \sqrt[4]{81}  - 8 \sqrt[3]{216}  + 15 \sqrt[5]{32}  +  \sqrt{225}

\sf \colorbox{pink} {Answer .4 }

\textbf{Given:} \sqrt[4]{81}  - 8 \sqrt[3]{216}  + 15 \sqrt[5]{32}  +  \sqrt{225}

Solution:

=  \sqrt[4]{ {3}^{4} }  - 8

=   \sqrt[3]{ {6}^{3} }  + 15

=  \sqrt[5]{ {2}^{5} }  +  \sqrt{ {15}^{2} }

= 3 - 8 \times 6 + 15 \times 2 + 15

= 3 - 48 + 30 + 15 = 0

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\\  \\  \\  \\  \\  \\  \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}



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