1.

Simplify: sin³Ф+cos³Ф/sinФ+cosФ + sinФcosФ

Answer» GIVEN :

sin³Ф+cos³Ф/sinФ+cosФ + sinФcosФ

To find :

  • simplify

SOLUTION :

As A,B and C ARC the INTERIOR angles of ΔABC,

➵ A + B + C = 180°

➵ B + C = 180° - A

➵ B + C = 90° - A/2..........(I)

➵ Now, sin B + C/2

➵ sin(90° - A/2) (using (i))

➵ sin B + C/2

➵ cos A/2 ( sin (90°- ø) = cos ø. )

Extra information :

  • sinø = Cos(90° - ø)

  • COS6= sin(90° - ø)

  • tanø = cot(90° - ø)

  • cotø = tan(90° - ø)

  • secø = cosec(90° - ø)

  • tanø = sinø/cosø

  • secø = 1/cosø

  • cotø = 1/tanø = sinø/cosø

  • 1 - tan(ø/2)/1 - tan(ø/2) = ±√1 - sinø/1 + sinø

  • tan ø/2 = ±√1 - cosø/1 + cosø


Discussion

No Comment Found

Related InterviewSolutions