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Simplify: :If x+1/x=4 evaluate (а) (x-1/x) (b) (x? +l/x?) |
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Answer»
This implies that x2+2ax=4x−4a−13 or x2+2ax−4x+4a+13=0 or x2+(2a−4)X+(4a+13)=0 Since the EQUATION has just ONE solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0. Hence we get that (2a−4)2=4⋅1⋅(4a+13) or 4a2−16a+16=16a+52 or 4a2−32a−36=0 or a2−8a−9=0 or (a−9)(a+1)=0 So the values of a are −1 and 9.
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