Simplify and write tye answer in exponential formPlease solve the numb

1.	Simplify and write tye answer in exponential formPlease solve the number ⬆️.No spam please ❌️@Fiza100 @Sk2
Answer» $\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$ $\tt Simplify\: and \:write\: the\: answer\: in\: exponential\: form$ $\bf \Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}$ $\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$ $\sf \bf \implies \Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}$ $\sf \bf \implies \bigg(\dfrac{{2}^{5}}{{2}^{8}}\bigg) \times {2}^{-5}$ ${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: \dfrac{{a}^{m}}{{a}^{n}} = {a}^{m-n}}}}}}$ $\sf \bf \implies \Big({2}^{5-8}\Big) \times {2}^{-5}$ $\sf \bf \implies {2}^{-3} \times {2}^{-5}$ ${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: {a}^{m}\times {a}^{n}= {a}^{m+n}}}}}}$ $\sf \bf \implies {2}^{-3+ \big(-5 \big)}$ $\sf \bf \implies {2}^{-3-5}$ $\sf \bf \implies {2}^{-8}$ ${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: \bf {a}^{-m} =\dfrac{1}{{a}^{m}}}}}}}$ $\implies {\boxed {\boxed {\color {aqua} {\sf \bf \dfrac{1}{{2}^{8}}}}}}$ ${\underbrace {\color {red} {\overline {\color {red} {\underline {\color {red} {\sf \therefore The\:exponential\:form \:of \:\Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}\:is\:\dfrac{1}{{2}^{8}}}}}}}}}$ $\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$ __________________________________________ $\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$ $\bf {a}^{m} \times {a}^{n} ={a}^{m+n}$ $\bf \dfrac{{a}^{m}}{{a}^{n}} ={a}^{m-n}$ $\bf \big({a}^{m}\big)^{n} ={a}^{mn}$ $\bf {a}^{-m} =\dfrac{1}{{a}^{m}}$ $\bf {a}^{m} \times {b}^{m} ={ab}^{m}$

Simplify and write tye answer in exponential formPlease solve the number ⬆️.No spam please ❌️@Fiza100 @Sk2

Answer»

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt Simplify\: and \:write\: the\: answer\: in\: exponential\: form$

$\bf \Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf \implies \Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}$

$\sf \bf \implies \bigg(\dfrac{{2}^{5}}{{2}^{8}}\bigg) \times {2}^{-5}$

${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: \dfrac{{a}^{m}}{{a}^{n}} = {a}^{m-n}}}}}}$

$\sf \bf \implies \Big({2}^{5-8}\Big) \times {2}^{-5}$

$\sf \bf \implies {2}^{-3} \times {2}^{-5}$

${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: {a}^{m}\times {a}^{n}= {a}^{m+n}}}}}}$

$\sf \bf \implies {2}^{-3+ \big(-5 \big)}$

$\sf \bf \implies {2}^{-3-5}$

$\sf \bf \implies {2}^{-8}$

${\color {blue} {\boxed {\boxed {\boxed {\sf Using \: \: \bf {a}^{-m} =\dfrac{1}{{a}^{m}}}}}}}$

$\implies {\boxed {\boxed {\color {aqua} {\sf \bf \dfrac{1}{{2}^{8}}}}}}$

${\underbrace {\color {red} {\overline {\color {red} {\underline {\color {red} {\sf \therefore The\:exponential\:form \:of \:\Big({2}^{5} \div {2}^{8}\Big) \times {2}^{-5}\:is\:\dfrac{1}{{2}^{8}}}}}}}}}$