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Simplify and write in the form of \(\frac {a^m}{a^n} = a^{m-n} \,or\, \frac {a^m}{a^n} = \frac {1}{a^{n-m}}\) : \(\frac {2^9}{2^3}\) |
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Answer» \(\frac {2^9}{2^3}\) = 29-3 [∵ \( \frac {a^m}{a^n} = a^{m-n}\)] = 26 |
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