Simplify: [8(5/6)] – [3(3/8)] + [1(7/12)]

1.	Simplify: [8(5/6)] – [3(3/8)] + [1(7/12)]
Answer» [8(5/6)] – [3(3/8)] + [1(7/12)] First convert each mixed fraction into improper fraction. We get, = [8(5/6)] = (53/6) = [3(3/8)] = (27/8) = [1(7/12)] = (19/12) Then, (53/6)- (27/8) – (19/12) LCM of 6, 8, 12 = 24 Now, let us change each of the given fraction into an equivalent fraction having 24 as the denominator. = [(53/6) × (4/4)] = (212/24) = [(27/8) × (3/3)] = (81/ 24) = [(19/12) × (2/2)] = (38/24) Now, = (212/24) – (81/ 24) – (38/24) = [(212- 81+ 38)/24] = [(250-81/24)] = (169/24) = [7(1/24)]

Answer»

[8(5/6)] – [3(3/8)] + [1(7/12)]

First convert each mixed fraction into improper fraction.

We get,

= [8(5/6)] = (53/6)

= [3(3/8)] = (27/8)

= [1(7/12)] = (19/12)

Then,

(53/6)- (27/8) – (19/12)

LCM of 6, 8, 12 = 24

Now, let us change each of the given fraction into an equivalent fraction having 24 as the denominator.

= [(53/6) × (4/4)] = (212/24)

= [(27/8) × (3/3)] = (81/ 24)

= [(19/12) × (2/2)] = (38/24)

Now,

= (212/24) – (81/ 24) – (38/24)

= [(212- 81+ 38)/24]

= [(250-81/24)]

= (169/24)

= [7(1/24)]

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