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Simplify √38 + √48 -----------------√8 + √12 |
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Answer» Answer: HEYA mate here is UR answer Step-by-step explanation: \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}} = $2$ Explanation: Simplification of \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}} = \frac{\sqrt{4\times8}+\sqrt{4\times12}}{\sqrt{8}+\sqrt{12}} =\frac{\sqrt{4}\times\sqrt{8}+\sqrt{4}\times\sqrt{12}}{\sqrt{8}+\sqrt{12}} Take√4common, we get = \frac{\sqrt{4}(\sqrt{8}+\sqrt{12})}{(\sqrt{8}+\sqrt{12})} After cancellation,weget =\sqrt{4} = $2$ Therefore, \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}} = $2$ ••• mark as brainliest ARMY.... |
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