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Silver crystallises in a face centred cubic unit cell. Each side of the unit cell has a length of 409 pm. What is the radius of an atom of silver? (Assume that each face centred atom is touching the four corner atoms.) |
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Answer» For face centred cubic unit cell (fcc) Radius (r) =`(a)/(2sqrt2)=(("409 pm"))/(2sqrt2)` `=(("409 pm"))/(2xx1.414)=144.6"pm"` |
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