1.

Sides of a triangle are in the ratio 12;17:25 and its perimeter is 540cm. find its area...?​

Answer»

\huge \underline{ \mathbb{SOLUTION:-}}

Given:

  • Sides of a TRIANGLE are in the ratio of 12:17:25
  • Perimeter of the triangle is 540cm

Need to find:

  • Area of the triangle

STEP by step explanation:

a = 12x

b = 17x

c = 25X

Perimeter = 540cm

a+b+c = 540

12x + 17x + 25x = 540

\large \implies{54x = 540}

\large \implies{x = \frac{540}{54}} \\ \large \implies{x = 10}

Therefore, sides are -

a = 10×12 = 120cm

b = 10×17 = 170cm

c= 25×10 = 250cm

Area of ∆\small \implies{ \sqrt{s(s - a)(s - b)(s - c)}} \\ \small \implies{ \sqrt{270(270 - 120)(270 - 170)(270 - 250)}}

\small \implies{ \sqrt{270(150)(100)(20)}} \\ \small \implies{ \sqrt{81000000}} \\ \small \implies{\bold{9000 {cm}^{2} }}


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