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Shows a square loop having 100 turns, an area of `2.5 xx10^(-3) m^2` and a resistance of `100 Omega`. The magnetic field has a magnitude B =0.40 T. Find the work done in pulling the loop out of the field, slowly and uniformly is 1.0 s. A. (a) `0`B. (b) `1mJ`C. ( c) `1muJ`D. (d) 0.1mJ` |
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Answer» Correct Answer - D (d) `W = Fl(NIBl)l = NBl^(2)((BVNl)/(R ))` `=(N^(2)B^(2)l^(2))/(R )V = (N^(2)B^(2)l^(3))/(R ) (l)/(t) = (N^(2)B^(2)l^(4))/(R t) = 0.1mJ` |
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