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Shows a particular position of 200 mm connecting rod AB and 80 mm long crank BC. At this position, the connecting rod of the engine experience a force of 3000 N on the crank pin at B. Find its (a) horizontal and vertical component (b) component along BC and normal to it. |
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Answer» The force of 3000 N acts along line AB. Let AB make angle α with horizontal. Then, obviously 200 sin α = 80 sin 60° ∴ α = 20.268° Referring to we get Horizontal component = 3000 cos 20.268° = 2814.2 N Vertical component = 3000 sin 20.268° = 1039.2 N Components along and normal to crank: The force makes angle α + 60° = 20.268 + 60 = 80.268° with crank. ∴ Component along crank = 3000 cos 80.268° = 507.1 N Component normal to crank = 3000 sin 80.268° = 2956.8 N |
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