Shown are the trajectories of projectile. Which have a maximum time of

1.	Shown are the trajectories of projectile. Which have a maximum time of flight?
Answer» T₁=T₂=T₃Explanation:SINCE the HEIGHT is same;we have H₁=H₂=H₃H=u²sin²θ/2gH₁=H₂=H₃ =>u₁²sin²θ₁=u₂²sin²θ₂=u₃²sin²θ₃ =>u₁sinθ₁=u₂sinθ₂=u₃sinθ₃T₁/T₂=2u₁sinθ₁/2u₂sinθ₂=1T₁=T₂ SIMILARLY T₁=T₃therefore;T₁=T₂=T₃

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Shown are the trajectories of projectile. Which have a maximum time of flight?

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