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Show the formation of Na2 O by the transfer of electrons

Answer» Atomic number of Sodium (Na) – 11Electronic configuration of Sodium – 1s2 2s2 2p6 3s1It has one valence electron, it will lose one electron to get octet configurationAtomic number of Oxygen (O) – 8Electronic configuration of Oxygen – 1s2 2s2 2p4It is two electrons short of octet configuration, thus it will gain two electrons.During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.2 Na -2e- → 2Na+O + 2e- → O-2\xa02Na+ + O-2 → Na2O


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