Show that the total power in AM is \(\frac{3}{2}\).

1.	Show that the total power in AM is \(\frac{3}{2}\).
Answer» Total power, P_T = P_c\((1+\frac{m^2_a}{2})\) For m_a = 1, P_T = P_c\((1+ \frac{1^2}{2})\) P_T = \(\frac{3}{2}\)P_c. ∴ Total power in AM is \(\frac{3}{2}\)

Answer»

Total power,

P_T = P_c\((1+\frac{m^2_a}{2})\)

For m_a = 1,

P_T = P_c\((1+ \frac{1^2}{2})\)

P_T = \(\frac{3}{2}\)P_c.

∴ Total power in AM is \(\frac{3}{2}\)

Discussion