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Show that the system of equations – x + 2y + 2 = 0 and \(\frac{1}{2}x\) − \(\frac{1}{2}y\) − 1 = 0 has a unique solution. |
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Answer» Given system of equations are – x + 2y + 2 = 0 and \(\frac{1}{2}\) x – \(\frac{1}{2}\) y – 1 = 0. By comparing given system of equations with a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, We get a1 = –1, b1 = 2, c1 = 2 and a2 = 1 2 , b2 = – 1 2 , c2 = – 1. Now,\(\frac{a_2}{a_2}\)= \(\frac{-1}{\frac{1}{2}}\) = −2, And \(\frac{b_1}{b_2}\) = \(\frac{2}{\frac{-1}{2}}\) = –4. Hence, \(\frac{a_2}{a_2}\) ≠ \(\frac{b_1}{b_2}\) which is condition of unique solution . Therefore the given system of equations has a unique solution. |
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