Show that the square of any positive integer cannot be of the form (5q

1.	Show that the square of any positive integer cannot be of the form (5q + 2) or (5q + 3) for any integer q.
Answer» Step-by-step EXPLANATION: $25q^{2}+25q+6$ (5q+2)or(5q+3) Apply the distributive PROPERTY by multiplying each term of 5q+2 by each term of 5q+3. $25q^{2}+15q+<klux>10Q</klux>+6$ Combine 15q and 10q to get 25q. $25q^{2}+25q+6$ Your ANSWER I HOPE right answer please mark brillint

Show that the square of any positive integer cannot be of the form (5q + 2) or (5q + 3) for any integer q.

Answer»

Step-by-step EXPLANATION:

$25q^{2}+25q+6$

(5q+2)or(5q+3)

Apply the distributive PROPERTY by multiplying each term of 5q+2 by each term of 5q+3.

$25q^{2}+15q+<klux>10Q</klux>+6$

Combine 15q and 10q to get 25q.

$25q^{2}+25q+6$

Your ANSWER I HOPE right answer please mark brillint

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Show that the square of any positive integer cannot be of the form (5q + 2) or (5q + 3) for any integer q.​

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Show that the square of any positive integer cannot be of the form (5q + 2) or (5q + 3) for any integer q.