Show that the points A (1, 2), B ( – 1, – 16) and C (0, – 7) lie

1.	Show that the points A (1, 2), B ( – 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.
Answer» We have the equation, y = 9x – 7 For A (1, 2), Substituting the values of (x,y) = (1, 2), We get, 2 = 9(1) – 7 = 9 – 7 = 2 For B (–1, –16), Substituting the values of (x,y) = (–1, –16), We get, –16 = 9(–1) – 7 = – 9 – 7 = – 16 For C (0, –7), Substituting the values of (x,y) = (0, –7), We get, – 7 = 9(0) – 7 = 0 – 7 = – 7 Hence, we find that the points A (1, 2), B (–1, –16) and C (0, –7) satisfies the line y = 9x – 7. Hence, A (1, 2), B (–1, –16) and C (0, –7) are solutions of the linear equation y = 9x – 7 Therefore, points A (1, 2), B (–1, –16), C (0, –7) lie on the graph of linear equation y = 9x – 7.

Show that the points A (1, 2), B ( – 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.

Answer»

We have the equation,

y = 9x – 7

For A (1, 2),

Substituting the values of (x,y) = (1, 2),

We get,

2 = 9(1) – 7 = 9 – 7 = 2

For B (–1, –16),

Substituting the values of (x,y) = (–1, –16),

We get,

–16 = 9(–1) – 7 = – 9 – 7 = – 16

For C (0, –7),

Substituting the values of (x,y) = (0, –7),

We get,

– 7 = 9(0) – 7 = 0 – 7 = – 7

Hence, we find that the points A (1, 2), B (–1, –16) and C (0, –7) satisfies the line y = 9x – 7.

Hence, A (1, 2), B (–1, –16) and C (0, –7) are solutions of the linear equation y = 9x – 7

Therefore, points A (1, 2), B (–1, –16), C (0, –7) lie on the graph of linear equation y = 9x – 7.